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109127414256243 = 336375804752081
BaseRepresentation
bin11000110100000000110100…
…110000110001001001110011
3112022101110221010112012122120
4120310000310300301021303
5103300420421022144433
61024032235251005323
731662124025211405
oct3064006460611163
9468343833465576
10109127414256243
1131853749446919
12102a575a299843
1348b7895289466
141cd3b1b7d2b75
15c939c3ce87b3
hex634034c31273

109127414256243 has 4 divisors (see below), whose sum is σ = 145503219008328. Its totient is φ = 72751609504160.

The previous prime is 109127414256209. The next prime is 109127414256283. The reversal of 109127414256243 is 342652414721901.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 109127414256243 - 213 = 109127414248051 is a prime.

It is not an unprimeable number, because it can be changed into a prime (109127414256283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18187902376038 + ... + 18187902376043.

It is an arithmetic number, because the mean of its divisors is an integer number (36375804752082).

Almost surely, 2109127414256243 is an apocalyptic number.

109127414256243 is a deficient number, since it is larger than the sum of its proper divisors (36375804752085).

109127414256243 is an equidigital number, since it uses as much as digits as its factorization.

109127414256243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36375804752084.

The product of its (nonzero) digits is 2903040, while the sum is 51.

The spelling of 109127414256243 in words is "one hundred nine trillion, one hundred twenty-seven billion, four hundred fourteen million, two hundred fifty-six thousand, two hundred forty-three".

Divisors: 1 3 36375804752081 109127414256243