Base | Representation |
---|---|
bin | 110010110110101010… |
… | …1001000010101100001 |
3 | 101102212220221110121011 |
4 | 1211231111020111201 |
5 | 3242124330004423 |
6 | 122100351500521 |
7 | 10614200256565 |
oct | 1455525102541 |
9 | 342786843534 |
10 | 109208438113 |
11 | 42351352a35 |
12 | 191b9827741 |
13 | a3b550c9a8 |
14 | 54000136a5 |
15 | 2c9288ab0d |
hex | 196d548561 |
109208438113 has 2 divisors, whose sum is σ = 109208438114. Its totient is φ = 109208438112.
The previous prime is 109208438063. The next prime is 109208438137. The reversal of 109208438113 is 311834802901.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 55153583104 + 54054855009 = 234848^2 + 232497^2 .
It is an emirp because it is prime and its reverse (311834802901) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 109208438113 - 213 = 109208429921 is a prime.
It is not a weakly prime, because it can be changed into another prime (109208438813) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54604219056 + 54604219057.
It is an arithmetic number, because the mean of its divisors is an integer number (54604219057).
Almost surely, 2109208438113 is an apocalyptic number.
It is an amenable number.
109208438113 is a deficient number, since it is larger than the sum of its proper divisors (1).
109208438113 is an equidigital number, since it uses as much as digits as its factorization.
109208438113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 40.
The spelling of 109208438113 in words is "one hundred nine billion, two hundred eight million, four hundred thirty-eight thousand, one hundred thirteen".
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