Base | Representation |
---|---|
bin | 10100010111010111… |
… | …00101101011010011 |
3 | 1001012222002222011101 |
4 | 22023223211223103 |
5 | 134342422103011 |
6 | 5004524325231 |
7 | 534640213432 |
oct | 121353455323 |
9 | 31188088141 |
10 | 10933394131 |
11 | 4700685920 |
12 | 21516a3817 |
13 | 10531a69aa |
14 | 75a0d3119 |
15 | 43ecd42c1 |
hex | 28bae5ad3 |
10933394131 has 4 divisors (see below), whose sum is σ = 11927339064. Its totient is φ = 9939449200.
The previous prime is 10933394119. The next prime is 10933394137. The reversal of 10933394131 is 13149333901.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10933394131 - 25 = 10933394099 is a prime.
It is a super-2 number, since 2×109333941312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10933394137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 496972450 + ... + 496972471.
It is an arithmetic number, because the mean of its divisors is an integer number (2981834766).
Almost surely, 210933394131 is an apocalyptic number.
10933394131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
10933394131 is a deficient number, since it is larger than the sum of its proper divisors (993944933).
10933394131 is an equidigital number, since it uses as much as digits as its factorization.
10933394131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 993944932.
The product of its (nonzero) digits is 26244, while the sum is 37.
The spelling of 10933394131 in words is "ten billion, nine hundred thirty-three million, three hundred ninety-four thousand, one hundred thirty-one".
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