Base | Representation |
---|---|
bin | 110010111100010101… |
… | …1011001100111000101 |
3 | 101110101012012010212122 |
4 | 1211320223121213011 |
5 | 3243022044403123 |
6 | 122131312255325 |
7 | 10622001446603 |
oct | 1457053314705 |
9 | 343335163778 |
10 | 109398825413 |
11 | 4243986a809 |
12 | 19251541545 |
13 | a415aac7b7 |
14 | 541b412873 |
15 | 2ca4446bc8 |
hex | 1978ad99c5 |
109398825413 has 2 divisors, whose sum is σ = 109398825414. Its totient is φ = 109398825412.
The previous prime is 109398825409. The next prime is 109398825421. The reversal of 109398825413 is 314528893901.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 105756340804 + 3642484609 = 325202^2 + 60353^2 .
It is a cyclic number.
It is not a de Polignac number, because 109398825413 - 22 = 109398825409 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (109398825443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54699412706 + 54699412707.
It is an arithmetic number, because the mean of its divisors is an integer number (54699412707).
Almost surely, 2109398825413 is an apocalyptic number.
It is an amenable number.
109398825413 is a deficient number, since it is larger than the sum of its proper divisors (1).
109398825413 is an equidigital number, since it uses as much as digits as its factorization.
109398825413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1866240, while the sum is 53.
The spelling of 109398825413 in words is "one hundred nine billion, three hundred ninety-eight million, eight hundred twenty-five thousand, four hundred thirteen".
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