10940541313 has 4 divisors (see below), whose sum is σ = 11782121428. Its totient is φ = 10098961200.

The previous prime is 10940541281. The next prime is 10940541319. The reversal of 10940541313 is 31314504901.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31314504901 = 163 ⋅192113527.

It can be written as a sum of positive squares in 2 ways, for example, as 7573872784 + 3366668529 = 87028^2 + 58023^2 .

It is a cyclic number.

It is not a de Polignac number, because 10940541313 - 2⁵ = 10940541281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10940541319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 420790038 + ... + 420790063.

It is an arithmetic number, because the mean of its divisors is an integer number (2945530357).

Almost surely, 2^10940541313 is an apocalyptic number.

10940541313 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

10940541313 is a deficient number, since it is larger than the sum of its proper divisors (841580115).

10940541313 is an equidigital number, since it uses as much as digits as its factorization.

10940541313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 841580114.

The product of its (nonzero) digits is 6480, while the sum is 31.

It can be divided in two parts, 109405413 and 13, that multiplied together give a square (1422270369 = 37713²).

The spelling of 10940541313 in words is "ten billion, nine hundred forty million, five hundred forty-one thousand, three hundred thirteen".