Base | Representation |
---|---|
bin | 10100011100101111… |
… | …10010001010100011 |
3 | 1001100010001022111021 |
4 | 22032113302022203 |
5 | 134441001042201 |
6 | 5013220030311 |
7 | 536025666622 |
oct | 121627621243 |
9 | 31303038437 |
10 | 10978534051 |
11 | 4724107141 |
12 | 2164832397 |
13 | 105c64cbc4 |
14 | 7620c36b9 |
15 | 443c4dea1 |
hex | 28e5f22a3 |
10978534051 has 2 divisors, whose sum is σ = 10978534052. Its totient is φ = 10978534050.
The previous prime is 10978534033. The next prime is 10978534079. The reversal of 10978534051 is 15043587901.
10978534051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10978534051 - 25 = 10978534019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10978533989 and 10978534007.
It is not a weakly prime, because it can be changed into another prime (10978534081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5489267025 + 5489267026.
It is an arithmetic number, because the mean of its divisors is an integer number (5489267026).
Almost surely, 210978534051 is an apocalyptic number.
10978534051 is a deficient number, since it is larger than the sum of its proper divisors (1).
10978534051 is an equidigital number, since it uses as much as digits as its factorization.
10978534051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 151200, while the sum is 43.
The spelling of 10978534051 in words is "ten billion, nine hundred seventy-eight million, five hundred thirty-four thousand, fifty-one".
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