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10991983 is a prime number
BaseRepresentation
bin101001111011…
…100101101111
3202200110011111
4221323211233
510303220413
61031332451
7162300412
oct51734557
922613144
1010991983
116228492
123821127
13237b242
141661b79
15e71d3d
hexa7b96f

10991983 has 2 divisors, whose sum is σ = 10991984. Its totient is φ = 10991982.

The previous prime is 10991951. The next prime is 10991987. The reversal of 10991983 is 38919901.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10991983 - 25 = 10991951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10991987) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5495991 + 5495992.

It is an arithmetic number, because the mean of its divisors is an integer number (5495992).

Almost surely, 210991983 is an apocalyptic number.

10991983 is a deficient number, since it is larger than the sum of its proper divisors (1).

10991983 is an equidigital number, since it uses as much as digits as its factorization.

10991983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17496, while the sum is 40.

The square root of 10991983 is about 3315.4159618365. The cubic root of 10991983 is about 222.3439666883.

The spelling of 10991983 in words is "ten million, nine hundred ninety-one thousand, nine hundred eighty-three".