Base | Representation |
---|---|
bin | 10100011111010011… |
… | …00011001000011011 |
3 | 1001101121101021201201 |
4 | 22033221203020123 |
5 | 140011442441113 |
6 | 5015303255031 |
7 | 536406121243 |
oct | 121751431033 |
9 | 31347337651 |
10 | 10999968283 |
11 | 4735216a87 |
12 | 216ba4a477 |
13 | 1063c16095 |
14 | 764ca2b23 |
15 | 445a84cdd |
hex | 28fa6321b |
10999968283 has 2 divisors, whose sum is σ = 10999968284. Its totient is φ = 10999968282.
The previous prime is 10999968271. The next prime is 10999968341. The reversal of 10999968283 is 38286999901.
10999968283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (38286999901) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10999968283 - 25 = 10999968251 is a prime.
It is not a weakly prime, because it can be changed into another prime (10999968233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5499984141 + 5499984142.
It is an arithmetic number, because the mean of its divisors is an integer number (5499984142).
Almost surely, 210999968283 is an apocalyptic number.
10999968283 is a deficient number, since it is larger than the sum of its proper divisors (1).
10999968283 is an equidigital number, since it uses as much as digits as its factorization.
10999968283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15116544, while the sum is 64.
The spelling of 10999968283 in words is "ten billion, nine hundred ninety-nine million, nine hundred sixty-eight thousand, two hundred eighty-three".
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