1100000000003 has 2 divisors, whose sum is σ = 1100000000004. Its totient is φ = 1100000000002.

The previous prime is 1099999999999. The next prime is 1100000000027. The reversal of 1100000000003 is 3000000000011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1100000000003 - 2² = 1099999999999 is a prime.

It is not a weakly prime, because it can be changed into another prime (1100000000303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550000000001 + 550000000002.

It is an arithmetic number, because the mean of its divisors is an integer number (550000000002).

Almost surely, 2^{1100000000003} is an apocalyptic number.

1100000000003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100000000003 is an equidigital number, since it uses as much as digits as its factorization.

1100000000003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 5.

Adding to 1100000000003 its reverse (3000000000011), we get a palindrome (4100000000014).

The spelling of 1100000000003 in words is "one trillion, one hundred billion, three", and thus it is an aban number.