Base | Representation |
---|---|
bin | 1010000000010010001100… |
… | …0110010011011000111111 |
3 | 1102221120220220211202100112 |
4 | 2200010203012103120333 |
5 | 2420211000011144103 |
6 | 35221155201420235 |
7 | 2213503154060513 |
oct | 240044306233077 |
9 | 42846826752315 |
10 | 11000000099903 |
11 | 356108a317a81 |
12 | 1297a5993a67b |
13 | 61a3ac45a679 |
14 | 2a058d5a0143 |
15 | 1412066c8cd8 |
hex | a012319363f |
11000000099903 has 2 divisors, whose sum is σ = 11000000099904. Its totient is φ = 11000000099902.
The previous prime is 11000000099897. The next prime is 11000000099969. The reversal of 11000000099903 is 30999000000011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11000000099903 - 24 = 11000000099887 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11000000099903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000000099303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500000049951 + 5500000049952.
It is an arithmetic number, because the mean of its divisors is an integer number (5500000049952).
Almost surely, 211000000099903 is an apocalyptic number.
11000000099903 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000000099903 is an equidigital number, since it uses as much as digits as its factorization.
11000000099903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2187, while the sum is 32.
Adding to 11000000099903 its reverse (30999000000011), we get a palindrome (41999000099914).
The spelling of 11000000099903 in words is "eleven trillion, ninety-nine thousand, nine hundred three".
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