11000000113 has 4 divisors (see below), whose sum is σ = 11029024240. Its totient is φ = 10970975988.

The previous prime is 11000000107. The next prime is 11000000119. The reversal of 11000000113 is 31100000011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31100000011 = 11071 ⋅2809141.

It is an interprime number because it is at equal distance from previous prime (11000000107) and next prime (11000000119).

It is a cyclic number.

It is not a de Polignac number, because 11000000113 - 2¹³ = 10999991921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11000000096 and 11000000105.

It is not an unprimeable number, because it can be changed into a prime (11000000119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14511495 + ... + 14512252.

It is an arithmetic number, because the mean of its divisors is an integer number (2757256060).

Almost surely, 2^11000000113 is an apocalyptic number.

It is an amenable number.

11000000113 is a deficient number, since it is larger than the sum of its proper divisors (29024127).

11000000113 is an equidigital number, since it uses as much as digits as its factorization.

11000000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29024126.

The product of its (nonzero) digits is 3, while the sum is 7.

Adding to 11000000113 its reverse (31100000011), we get a palindrome (42100000124).

It can be divided in two parts, 1100000011 and 3, that multiplied together give a palindrome (3300000033).

The spelling of 11000000113 in words is "eleven billion, one hundred thirteen", and thus it is an aban number.