Base | Representation |
---|---|
bin | 10100011111010011… |
… | …01011000111010111 |
3 | 1001101121102221120211 |
4 | 22033221223013113 |
5 | 140012000012413 |
6 | 5015304110251 |
7 | 536406315466 |
oct | 121751530727 |
9 | 31347387524 |
10 | 11000000983 |
11 | 4735239604 |
12 | 216ba65387 |
13 | 1063c27c2a |
14 | 764cb09dd |
15 | 445a8e83d |
hex | 28fa6b1d7 |
11000000983 has 2 divisors, whose sum is σ = 11000000984. Its totient is φ = 11000000982.
The previous prime is 11000000969. The next prime is 11000001007. The reversal of 11000000983 is 38900000011.
It is a weak prime.
It is an emirp because it is prime and its reverse (38900000011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11000000983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000000383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500000491 + 5500000492.
It is an arithmetic number, because the mean of its divisors is an integer number (5500000492).
Almost surely, 211000000983 is an apocalyptic number.
11000000983 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000000983 is an equidigital number, since it uses as much as digits as its factorization.
11000000983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 11000000983 its reverse (38900000011), we get a palindrome (49900000994).
The spelling of 11000000983 in words is "eleven billion, nine hundred eighty-three", and thus it is an aban number.
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