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11000021120197 is a prime number
BaseRepresentation
bin1010000000010010010001…
…0110011111010011000101
31102221120222101101200202221
42200010210112133103011
52420211020401321242
635221201232132341
72213503530536254
oct240044426372305
942846871350687
1011000021120197
1135610a017491a
121297a649970b1
1361a3b390a305
142a05922b279b
1514120847c167
hexa012459f4c5

11000021120197 has 2 divisors, whose sum is σ = 11000021120198. Its totient is φ = 11000021120196.

The previous prime is 11000021120191. The next prime is 11000021120213. The reversal of 11000021120197 is 79102112000011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10191890240676 + 808130879521 = 3192474^2 + 898961^2 .

It is an emirp because it is prime and its reverse (79102112000011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000021120197 - 23 = 11000021120189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000021120191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500010560098 + 5500010560099.

It is an arithmetic number, because the mean of its divisors is an integer number (5500010560099).

Almost surely, 211000021120197 is an apocalyptic number.

It is an amenable number.

11000021120197 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000021120197 is an equidigital number, since it uses as much as digits as its factorization.

11000021120197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 25.

The spelling of 11000021120197 in words is "eleven trillion, twenty-one million, one hundred twenty thousand, one hundred ninety-seven".