Base | Representation |
---|---|
bin | 1010000000010010010001… |
… | …0110011111100100000001 |
3 | 1102221120222101101202021002 |
4 | 2200010210112133210001 |
5 | 2420211020401340111 |
6 | 35221201232141345 |
7 | 2213503530542363 |
oct | 240044426374401 |
9 | 42846871352232 |
10 | 11000021121281 |
11 | 35610a0175715 |
12 | 1297a64997855 |
13 | 61a3b390a95a |
14 | 2a05922b2d33 |
15 | 14120847c63b |
hex | a012459f901 |
11000021121281 has 2 divisors, whose sum is σ = 11000021121282. Its totient is φ = 11000021121280.
The previous prime is 11000021121209. The next prime is 11000021121343. The reversal of 11000021121281 is 18212112000011.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10007226096400 + 992795024881 = 3163420^2 + 996391^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000021121281 - 218 = 11000020859137 is a prime.
It is a super-2 number, since 2×110000211212812 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11000021121181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500010560640 + 5500010560641.
It is an arithmetic number, because the mean of its divisors is an integer number (5500010560641).
Almost surely, 211000021121281 is an apocalyptic number.
It is an amenable number.
11000021121281 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000021121281 is an equidigital number, since it uses as much as digits as its factorization.
11000021121281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 20.
Adding to 11000021121281 its reverse (18212112000011), we get a palindrome (29212133121292).
The spelling of 11000021121281 in words is "eleven trillion, twenty-one million, one hundred twenty-one thousand, two hundred eighty-one".
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