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11000050115 = 52200010023
BaseRepresentation
bin10100011111010011…
…10111000111000011
31001101121112102222112
422033221313013003
5140012003100430
65015305125535
7536406611645
oct121751670703
931347472875
1011000050115
11473527250a
12216ba898ab
131063c443c2
14764cc4895
15445a9e195
hex28fa771c3

11000050115 has 4 divisors (see below), whose sum is σ = 13200060144. Its totient is φ = 8800040088.

The previous prime is 11000050099. The next prime is 11000050177. The reversal of 11000050115 is 51105000011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11000050115 - 24 = 11000050099 is a prime.

It is a super-2 number, since 2×110000501152 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11000050115.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1100005007 + ... + 1100005016.

It is an arithmetic number, because the mean of its divisors is an integer number (3300015036).

Almost surely, 211000050115 is an apocalyptic number.

11000050115 is a deficient number, since it is larger than the sum of its proper divisors (2200010029).

11000050115 is an equidigital number, since it uses as much as digits as its factorization.

11000050115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2200010028.

The product of its (nonzero) digits is 25, while the sum is 14.

Adding to 11000050115 its reverse (51105000011), we get a palindrome (62105050126).

The spelling of 11000050115 in words is "eleven billion, fifty thousand, one hundred fifteen".

Divisors: 1 5 2200010023 11000050115