Base | Representation |
---|---|
bin | 1010000000010010100100… |
… | …0001011001100011011011 |
3 | 1102221121011211211200002112 |
4 | 2200010221001121203123 |
5 | 2420211200431241343 |
6 | 35221213111422535 |
7 | 2213505501551666 |
oct | 240045101314333 |
9 | 42847154750075 |
10 | 11000099477723 |
11 | 3561130424004 |
12 | 1297a87084a4b |
13 | 61a3c6c13c05 |
14 | 2a059c86c6dd |
15 | 1412102a9218 |
hex | a01290598db |
11000099477723 has 2 divisors, whose sum is σ = 11000099477724. Its totient is φ = 11000099477722.
The previous prime is 11000099477707. The next prime is 11000099477753. The reversal of 11000099477723 is 32777499000011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11000099477723 - 24 = 11000099477707 is a prime.
It is not a weakly prime, because it can be changed into another prime (11000099477753) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500049738861 + 5500049738862.
It is an arithmetic number, because the mean of its divisors is an integer number (5500049738862).
Almost surely, 211000099477723 is an apocalyptic number.
11000099477723 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000099477723 is an equidigital number, since it uses as much as digits as its factorization.
11000099477723 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 666792, while the sum is 50.
The spelling of 11000099477723 in words is "eleven trillion, ninety-nine million, four hundred seventy-seven thousand, seven hundred twenty-three".
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