Base | Representation |
---|---|
bin | 11001000000101110011010… |
… | …100001111010011001000111 |
3 | 112102110222210211012222220211 |
4 | 121000232122201322121013 |
5 | 103404224021444432142 |
6 | 1025541432313140251 |
7 | 32112211216414633 |
oct | 3100563241723107 |
9 | 472428724188824 |
10 | 110000999999047 |
11 | 32060186863293 |
12 | 10406b203ba687 |
13 | 494c08550b081 |
14 | 1d24110a8bdc3 |
15 | cab5a23e3917 |
hex | 640b9a87a647 |
110000999999047 has 2 divisors, whose sum is σ = 110000999999048. Its totient is φ = 110000999999046.
The previous prime is 110000999998991. The next prime is 110000999999063. The reversal of 110000999999047 is 740999999000011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110000999999047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110000999499047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000499999523 + 55000499999524.
It is an arithmetic number, because the mean of its divisors is an integer number (55000499999524).
Almost surely, 2110000999999047 is an apocalyptic number.
110000999999047 is a deficient number, since it is larger than the sum of its proper divisors (1).
110000999999047 is an equidigital number, since it uses as much as digits as its factorization.
110000999999047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14880348, while the sum is 67.
The spelling of 110000999999047 in words is "one hundred ten trillion, nine hundred ninety-nine million, nine hundred ninety-nine thousand, forty-seven".
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