11000100999997 has 2 divisors, whose sum is σ = 11000100999998. Its totient is φ = 11000100999996.

The previous prime is 11000100999991. The next prime is 11000101000043. The reversal of 11000100999997 is 79999900100011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7874651804761 + 3125449195236 = 2806181^2 + 1767894^2 .

It is an emirp because it is prime and its reverse (79999900100011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000100999997 - 2⁷ = 11000100999869 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000100999991) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500050499998 + 5500050499999.

It is an arithmetic number, because the mean of its divisors is an integer number (5500050499999).

Almost surely, 2^{11000100999997} is an apocalyptic number.

It is an amenable number.

11000100999997 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000100999997 is an equidigital number, since it uses as much as digits as its factorization.

11000100999997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 413343, while the sum is 55.

The spelling of 11000100999997 in words is "eleven trillion, one hundred million, nine hundred ninety-nine thousand, nine hundred ninety-seven".