1100010100083 has 4 divisors (see below), whose sum is σ = 1466680133448. Its totient is φ = 733340066720.

The previous prime is 1100010100081. The next prime is 1100010100169. The reversal of 1100010100083 is 3800010100011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1100010100083 - 2¹ = 1100010100081 is a prime.

It is a super-2 number, since 2×1100010100083² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1100010100081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183335016678 + ... + 183335016683.

It is an arithmetic number, because the mean of its divisors is an integer number (366670033362).

Almost surely, 2^{1100010100083} is an apocalyptic number.

1100010100083 is a deficient number, since it is larger than the sum of its proper divisors (366670033365).

1100010100083 is an equidigital number, since it uses as much as digits as its factorization.

1100010100083 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 366670033364.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 1100010100083 its reverse (3800010100011), we get a palindrome (4900020200094).

The spelling of 1100010100083 in words is "one trillion, one hundred billion, ten million, one hundred thousand, eighty-three".