Base | Representation |
---|---|
bin | 10000000000011101101… |
… | …101100001010101110001 |
3 | 10220011022121001220102211 |
4 | 100000131231201111301 |
5 | 121010310041200311 |
6 | 2201200534012121 |
7 | 142321163401564 |
oct | 20003555412561 |
9 | 3804277056384 |
10 | 1100010100081 |
11 | 39456a02a372 |
12 | 1592331a7041 |
13 | 7c965c03559 |
14 | 3b3529764db |
15 | 1d9317e8821 |
hex | 1001db61571 |
1100010100081 has 2 divisors, whose sum is σ = 1100010100082. Its totient is φ = 1100010100080.
The previous prime is 1100010100051. The next prime is 1100010100169. The reversal of 1100010100081 is 1800010100011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1068949210000 + 31060890081 = 1033900^2 + 176241^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100010100081 - 219 = 1100009575793 is a prime.
It is a super-2 number, since 2×11000101000812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1100010100051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005050040 + 550005050041.
It is an arithmetic number, because the mean of its divisors is an integer number (550005050041).
Almost surely, 21100010100081 is an apocalyptic number.
It is an amenable number.
1100010100081 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100010100081 is an equidigital number, since it uses as much as digits as its factorization.
1100010100081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 1100010100081 its reverse (1800010100011), we get a palindrome (2900020200092).
The spelling of 1100010100081 in words is "one trillion, one hundred billion, ten million, one hundred thousand, eighty-one".
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