110001021211121 has 2 divisors, whose sum is σ = 110001021211122. Its totient is φ = 110001021211120.

The previous prime is 110001021211051. The next prime is 110001021211157. The reversal of 110001021211121 is 121112120100011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104652490800400 + 5348530410721 = 10229980^2 + 2312689^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110001021211121 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 110001021211096 and 110001021211105.

It is not a weakly prime, because it can be changed into another prime (110001021211171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000510605560 + 55000510605561.

It is an arithmetic number, because the mean of its divisors is an integer number (55000510605561).

Almost surely, 2^{110001021211121} is an apocalyptic number.

It is an amenable number.

110001021211121 is a deficient number, since it is larger than the sum of its proper divisors (1).

110001021211121 is an equidigital number, since it uses as much as digits as its factorization.

110001021211121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 110001021211121 its reverse (121112120100011), we get a palindrome (231113141311132).

The spelling of 110001021211121 in words is "one hundred ten trillion, one billion, twenty-one million, two hundred eleven thousand, one hundred twenty-one".