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11000102443403 = 103106797111101
BaseRepresentation
bin1010000000010010100100…
…1100101101100110001011
31102221121012001102100020112
42200010221030231212023
52420211202211142103
635221213255144535
72213505536013203
oct240045114554613
942847161370215
1011000102443403
11356113206a187
121297a8807514b
1361a3c7711a58
142a059d001403
15141210692cd8
hexa012932d98b

11000102443403 has 4 divisors (see below), whose sum is σ = 11106899554608. Its totient is φ = 10893305332200.

The previous prime is 11000102443397. The next prime is 11000102443409. The reversal of 11000102443403 is 30434420100011.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (11000102443397) and next prime (11000102443409).

It is a cyclic number.

It is not a de Polignac number, because 11000102443403 - 214 = 11000102427019 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11000102443409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53398555448 + ... + 53398555653.

It is an arithmetic number, because the mean of its divisors is an integer number (2776724888652).

Almost surely, 211000102443403 is an apocalyptic number.

11000102443403 is a deficient number, since it is larger than the sum of its proper divisors (106797111205).

11000102443403 is a wasteful number, since it uses less digits than its factorization.

11000102443403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106797111204.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 11000102443403 its reverse (30434420100011), we get a palindrome (41434522543414).

The spelling of 11000102443403 in words is "eleven trillion, one hundred two million, four hundred forty-three thousand, four hundred three".

Divisors: 1 103 106797111101 11000102443403