110001083 has 2 divisors, whose sum is σ = 110001084. Its totient is φ = 110001082.

The previous prime is 110001079. The next prime is 110001097. The reversal of 110001083 is 380100011.

It is an a-pointer prime, because the next prime (110001097) can be obtained adding 110001083 to its sum of digits (14).

It is a weak prime.

It is an emirp because it is prime and its reverse (380100011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110001083 - 2² = 110001079 is a prime.

It is a super-2 number, since 2×110001083² = 24200476522345778, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (110001053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000541 + 55000542.

It is an arithmetic number, because the mean of its divisors is an integer number (55000542).

Almost surely, 2^110001083 is an apocalyptic number.

110001083 is a deficient number, since it is larger than the sum of its proper divisors (1).

110001083 is an equidigital number, since it uses as much as digits as its factorization.

110001083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 110001083 is about 10488.1401115736. The cubic root of 110001083 is about 479.1435581580.

Adding to 110001083 its reverse (380100011), we get a palindrome (490101094).

The spelling of 110001083 in words is "one hundred ten million, one thousand, eighty-three".