Base | Representation |
---|---|
bin | 1010000000010010100110… |
… | …1001100000111010010001 |
3 | 1102221121012120121221012002 |
4 | 2200010221221200322101 |
5 | 2420211211124243432 |
6 | 35221214125043345 |
7 | 2213505660130403 |
oct | 240045151407221 |
9 | 42847176557162 |
10 | 11000109993617 |
11 | 3561136356828 |
12 | 1297a8a6b6555 |
13 | 61a3c9156534 |
14 | 2a05a0008b73 |
15 | 141211184e62 |
hex | a0129a60e91 |
11000109993617 has 2 divisors, whose sum is σ = 11000109993618. Its totient is φ = 11000109993616.
The previous prime is 11000109993611. The next prime is 11000109993623. The reversal of 11000109993617 is 71639990100011.
It is a balanced prime because it is at equal distance from previous prime (11000109993611) and next prime (11000109993623).
It can be written as a sum of positive squares in only one way, i.e., 9918241656976 + 1081868336641 = 3149324^2 + 1040129^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000109993617 - 218 = 11000109731473 is a prime.
It is not a weakly prime, because it can be changed into another prime (11000109993611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500054996808 + 5500054996809.
It is an arithmetic number, because the mean of its divisors is an integer number (5500054996809).
Almost surely, 211000109993617 is an apocalyptic number.
It is an amenable number.
11000109993617 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000109993617 is an equidigital number, since it uses as much as digits as its factorization.
11000109993617 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 91854, while the sum is 47.
The spelling of 11000109993617 in words is "eleven trillion, one hundred nine million, nine hundred ninety-three thousand, six hundred seventeen".
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