Base | Representation |
---|---|
bin | 10000000000011101110… |
… | …001010111111010001111 |
3 | 10220011022122222012211101 |
4 | 100000131301113322033 |
5 | 121010310321010111 |
6 | 2201201011403531 |
7 | 142321205106211 |
oct | 20003561277217 |
9 | 3804278865741 |
10 | 1100011110031 |
11 | 39456a65a139 |
12 | 1592335b35a7 |
13 | 7c966198162 |
14 | 3b352b5a5b1 |
15 | 1d931947bc1 |
hex | 1001dc57e8f |
1100011110031 has 2 divisors, whose sum is σ = 1100011110032. Its totient is φ = 1100011110030.
The previous prime is 1100011109983. The next prime is 1100011110047. The reversal of 1100011110031 is 1300111100011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100011110031 - 27 = 1100011109903 is a prime.
It is a super-2 number, since 2×11000111100312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100011110061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005555015 + 550005555016.
It is an arithmetic number, because the mean of its divisors is an integer number (550005555016).
Almost surely, 21100011110031 is an apocalyptic number.
1100011110031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100011110031 is an equidigital number, since it uses as much as digits as its factorization.
1100011110031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 10.
Adding to 1100011110031 its reverse (1300111100011), we get a palindrome (2400122210042).
The spelling of 1100011110031 in words is "one trillion, one hundred billion, eleven million, one hundred ten thousand, thirty-one".
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