1100011121113 has 2 divisors, whose sum is σ = 1100011121114. Its totient is φ = 1100011121112.

The previous prime is 1100011121057. The next prime is 1100011121141. The reversal of 1100011121113 is 3111211100011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1048592384064 + 51418737049 = 1024008^2 + 226757^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100011121113 - 2¹⁷ = 1100010990041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100011121093 and 1100011121102.

It is not a weakly prime, because it can be changed into another prime (1100011125113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005560556 + 550005560557.

It is an arithmetic number, because the mean of its divisors is an integer number (550005560557).

Almost surely, 2^{1100011121113} is an apocalyptic number.

It is an amenable number.

1100011121113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100011121113 is an equidigital number, since it uses as much as digits as its factorization.

1100011121113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 1100011121113 its reverse (3111211100011), we get a palindrome (4211222221124).

The spelling of 1100011121113 in words is "one trillion, one hundred billion, eleven million, one hundred twenty-one thousand, one hundred thirteen".