Base | Representation |
---|---|
bin | 11001000000101110100001… |
… | …110100000111100100010101 |
3 | 112102111000010100012001201211 |
4 | 121000232201310013210111 |
5 | 103404224244241241432 |
6 | 1025541452400421421 |
7 | 32112214232254153 |
oct | 3100564164074425 |
9 | 472430110161654 |
10 | 110001122212117 |
11 | 32060239846824 |
12 | 10406b55317871 |
13 | 494c0a492b3b6 |
14 | 1d24122dc23d3 |
15 | cab5aced4d47 |
hex | 640ba1d07915 |
110001122212117 has 2 divisors, whose sum is σ = 110001122212118. Its totient is φ = 110001122212116.
The previous prime is 110001122212067. The next prime is 110001122212123. The reversal of 110001122212117 is 711212221100011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 109344959030596 + 656163181521 = 10456814^2 + 810039^2 .
It is a cyclic number.
It is not a de Polignac number, because 110001122212117 - 243 = 101205029189909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110001192212117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000561106058 + 55000561106059.
It is an arithmetic number, because the mean of its divisors is an integer number (55000561106059).
Almost surely, 2110001122212117 is an apocalyptic number.
It is an amenable number.
110001122212117 is a deficient number, since it is larger than the sum of its proper divisors (1).
110001122212117 is an equidigital number, since it uses as much as digits as its factorization.
110001122212117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 110001122212117 its reverse (711212221100011), we get a palindrome (821213343312128).
The spelling of 110001122212117 in words is "one hundred ten trillion, one billion, one hundred twenty-two million, two hundred twelve thousand, one hundred seventeen".
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