110001131 has 2 divisors, whose sum is σ = 110001132. Its totient is φ = 110001130.

The previous prime is 110001119. The next prime is 110001137. The reversal of 110001131 is 131100011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110001131 is a prime.

It is a super-2 number, since 2×110001131² = 24200497642558322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (110001137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000565 + 55000566.

It is an arithmetic number, because the mean of its divisors is an integer number (55000566).

Almost surely, 2^110001131 is an apocalyptic number.

110001131 is a deficient number, since it is larger than the sum of its proper divisors (1).

110001131 is an equidigital number, since it uses as much as digits as its factorization.

110001131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 8.

The square root of 110001131 is about 10488.1423998723. The cubic root of 110001131 is about 479.1436278509.

Adding to 110001131 its reverse (131100011), we get a palindrome (241101142).

The spelling of 110001131 in words is "one hundred ten million, one thousand, one hundred thirty-one".