Base | Representation |
---|---|
bin | 10000000000011101110… |
… | …101001001111000111111 |
3 | 10220011022201211120102201 |
4 | 100000131311021320333 |
5 | 121010311044214213 |
6 | 2201201044532331 |
7 | 142321216404652 |
oct | 20003565117077 |
9 | 3804281746381 |
10 | 1100012101183 |
11 | 394570176876 |
12 | 1592339b10a7 |
13 | 7c966454338 |
14 | 3b352d37899 |
15 | 1d931a916dd |
hex | 1001dd49e3f |
1100012101183 has 2 divisors, whose sum is σ = 1100012101184. Its totient is φ = 1100012101182.
The previous prime is 1100012101157. The next prime is 1100012101207. The reversal of 1100012101183 is 3811012100011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100012101183 is a prime.
It is a super-3 number, since 3×11000121011833 (a number of 37 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1100012101183.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100018101183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006050591 + 550006050592.
It is an arithmetic number, because the mean of its divisors is an integer number (550006050592).
Almost surely, 21100012101183 is an apocalyptic number.
1100012101183 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100012101183 is an equidigital number, since it uses as much as digits as its factorization.
1100012101183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 1100012101183 its reverse (3811012100011), we get a palindrome (4911024201194).
The spelling of 1100012101183 in words is "one trillion, one hundred billion, twelve million, one hundred one thousand, one hundred eighty-three".
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