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1100012838997 is a prime number
BaseRepresentation
bin10000000000011101110…
…111111110000001010101
310220011022210020001112011
4100000131313332001111
5121010311241321442
62201201112424221
7142321225600012
oct20003567760125
93804283201464
101100012838997
11394570630136
121592340a8071
137c966652107
143b35308a709
151d931b8a117
hex1001ddfe055

1100012838997 has 2 divisors, whose sum is σ = 1100012838998. Its totient is φ = 1100012838996.

The previous prime is 1100012838931. The next prime is 1100012839019. The reversal of 1100012838997 is 7998382100011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 786850606116 + 313162232881 = 887046^2 + 559609^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100012838997 - 215 = 1100012806229 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1100012838997.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100012898997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006419498 + 550006419499.

It is an arithmetic number, because the mean of its divisors is an integer number (550006419499).

Almost surely, 21100012838997 is an apocalyptic number.

It is an amenable number.

1100012838997 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100012838997 is an equidigital number, since it uses as much as digits as its factorization.

1100012838997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 217728, while the sum is 49.

The spelling of 1100012838997 in words is "one trillion, one hundred billion, twelve million, eight hundred thirty-eight thousand, nine hundred ninety-seven".