Base | Representation |
---|---|
bin | 11001000000101110101100… |
… | …101001110010100111101111 |
3 | 112102111000121000100121020211 |
4 | 121000232230221302213233 |
5 | 103404230132314214010 |
6 | 1025541522414123251 |
7 | 32112221601014155 |
oct | 3100565451624757 |
9 | 472430530317224 |
10 | 110001304054255 |
11 | 32060322457489 |
12 | 10406ba61b0527 |
13 | 494c1034c88b3 |
14 | 1d2413d1d93d5 |
15 | cab5bde5408a |
hex | 640baca729ef |
110001304054255 has 32 divisors (see below), whose sum is σ = 140694138648000. Its totient is φ = 82326164078592.
The previous prime is 110001304054223. The next prime is 110001304054259. The reversal of 110001304054255 is 552450403100011.
It is a cyclic number.
It is not a de Polignac number, because 110001304054255 - 25 = 110001304054223 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110001304054259) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9155562 + ... + 17430631.
It is an arithmetic number, because the mean of its divisors is an integer number (4396691832750).
Almost surely, 2110001304054255 is an apocalyptic number.
110001304054255 is a deficient number, since it is larger than the sum of its proper divisors (30692834593745).
110001304054255 is a wasteful number, since it uses less digits than its factorization.
110001304054255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26586763.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 110001304054255 its reverse (552450403100011), we get a palindrome (662451707154266).
The spelling of 110001304054255 in words is "one hundred ten trillion, one billion, three hundred four million, fifty-four thousand, two hundred fifty-five".
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