1100013100051 has 2 divisors, whose sum is σ = 1100013100052. Its totient is φ = 1100013100050.

The previous prime is 1100013100009. The next prime is 1100013100091. The reversal of 1100013100051 is 1500013100011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100013100051 is a prime.

It is a super-2 number, since 2×1100013100051² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1100013100091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006550025 + 550006550026.

It is an arithmetic number, because the mean of its divisors is an integer number (550006550026).

Almost surely, 2^{1100013100051} is an apocalyptic number.

1100013100051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100013100051 is an equidigital number, since it uses as much as digits as its factorization.

1100013100051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 13.

Adding to 1100013100051 its reverse (1500013100011), we get a palindrome (2600026200062).

The spelling of 1100013100051 in words is "one trillion, one hundred billion, thirteen million, one hundred thousand, fifty-one".