Base | Representation |
---|---|
bin | 10100011111010100… |
… | …01011001000011011 |
3 | 1001101121200121110212 |
4 | 22033222023020123 |
5 | 140012013211443 |
6 | 5015311001335 |
7 | 536410403021 |
oct | 121752131033 |
9 | 31347617425 |
10 | 11000132123 |
11 | 4735319092 |
12 | 216bb0924b |
13 | 1063c72826 |
14 | 764d06711 |
15 | 445ab8618 |
hex | 28fa8b21b |
11000132123 has 2 divisors, whose sum is σ = 11000132124. Its totient is φ = 11000132122.
The previous prime is 11000132119. The next prime is 11000132131. The reversal of 11000132123 is 32123100011.
11000132123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11000132123 - 22 = 11000132119 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11000132098 and 11000132107.
It is not a weakly prime, because it can be changed into another prime (11000132113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500066061 + 5500066062.
It is an arithmetic number, because the mean of its divisors is an integer number (5500066062).
Almost surely, 211000132123 is an apocalyptic number.
11000132123 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000132123 is an equidigital number, since it uses as much as digits as its factorization.
11000132123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 11000132123 its reverse (32123100011), we get a palindrome (43123232134).
The spelling of 11000132123 in words is "eleven billion, one hundred thirty-two thousand, one hundred twenty-three".
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