1100013220033 has 16 divisors (see below), whose sum is σ = 1353924611200. Its totient is φ = 870300153216.

The previous prime is 1100013219979. The next prime is 1100013220057. The reversal of 1100013220033 is 3300223100011.

It is a de Polignac number, because none of the positive numbers 2^k-1100013220033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100013219989 and 1100013220016.

It is not an unprimeable number, because it can be changed into a prime (1100013220093) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1799341 + ... + 2331877.

It is an arithmetic number, because the mean of its divisors is an integer number (84620288200).

Almost surely, 2^{1100013220033} is an apocalyptic number.

1100013220033 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1100013220033 is a deficient number, since it is larger than the sum of its proper divisors (253911391167).

1100013220033 is a wasteful number, since it uses less digits than its factorization.

1100013220033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 555256.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 1100013220033 its reverse (3300223100011), we get a palindrome (4400236320044).

The spelling of 1100013220033 in words is "one trillion, one hundred billion, thirteen million, two hundred twenty thousand, thirty-three".