Base | Representation |
---|---|
bin | 10000000000011101111… |
… | …001011011000011011001 |
3 | 10220011022210221102020111 |
4 | 100000131321123003121 |
5 | 121010311341020212 |
6 | 2201201124524321 |
7 | 142321232044663 |
oct | 20003571330331 |
9 | 3804283842214 |
10 | 1100013220057 |
11 | 394570870464 |
12 | 1592342506a1 |
13 | 7c9667566ab |
14 | 3b353149533 |
15 | 1d931c12ea7 |
hex | 1001de5b0d9 |
1100013220057 has 2 divisors, whose sum is σ = 1100013220058. Its totient is φ = 1100013220056.
The previous prime is 1100013219979. The next prime is 1100013220069. The reversal of 1100013220057 is 7500223100011.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 950272082761 + 149741137296 = 974819^2 + 386964^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100013220057 - 223 = 1100004831449 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100013226057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006610028 + 550006610029.
It is an arithmetic number, because the mean of its divisors is an integer number (550006610029).
Almost surely, 21100013220057 is an apocalyptic number.
It is an amenable number.
1100013220057 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100013220057 is an equidigital number, since it uses as much as digits as its factorization.
1100013220057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 420, while the sum is 22.
Adding to 1100013220057 its reverse (7500223100011), we get a palindrome (8600236320068).
The spelling of 1100013220057 in words is "one trillion, one hundred billion, thirteen million, two hundred twenty thousand, fifty-seven".
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