11000132433 has 12 divisors (see below), whose sum is σ = 16276619268. Its totient is φ = 7154557440.

The previous prime is 11000132401. The next prime is 11000132459. The reversal of 11000132433 is 33423100011.

11000132433 is a `hidden beast` number, since 1 + 100 + 0 + 132 + 433 = 666.

11000132433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 2074984704 + 8925147729 = 45552^2 + 94473^2 .

It is not a de Polignac number, because 11000132433 - 2⁵ = 11000132401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11000132483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 14904960 + ... + 14905697.

It is an arithmetic number, because the mean of its divisors is an integer number (1356384939).

Almost surely, 2^11000132433 is an apocalyptic number.

It is an amenable number.

11000132433 is a deficient number, since it is larger than the sum of its proper divisors (5276486835).

11000132433 is a wasteful number, since it uses less digits than its factorization.

11000132433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29810704 (or 29810701 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 11000132433 its reverse (33423100011), we get a palindrome (44423232444).

The spelling of 11000132433 in words is "eleven billion, one hundred thirty-two thousand, four hundred thirty-three".