1100014443613 has 2 divisors, whose sum is σ = 1100014443614. Its totient is φ = 1100014443612.

The previous prime is 1100014443557. The next prime is 1100014443617. The reversal of 1100014443613 is 3163444100011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 853400897209 + 246613546404 = 923797^2 + 496602^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100014443613 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100014443617) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550007221806 + 550007221807.

It is an arithmetic number, because the mean of its divisors is an integer number (550007221807).

Almost surely, 2^{1100014443613} is an apocalyptic number.

It is an amenable number.

1100014443613 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100014443613 is an equidigital number, since it uses as much as digits as its factorization.

1100014443613 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1100014443613 its reverse (3163444100011), we get a palindrome (4263458543624).

The spelling of 1100014443613 in words is "one trillion, one hundred billion, fourteen million, four hundred forty-three thousand, six hundred thirteen".