11000200109 has 2 divisors, whose sum is σ = 11000200110. Its totient is φ = 11000200108.

The previous prime is 11000200093. The next prime is 11000200121. The reversal of 11000200109 is 90100200011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9497087209 + 1503112900 = 97453^2 + 38770^2 .

It is an emirp because it is prime and its reverse (90100200011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000200109 - 2⁴ = 11000200093 is a prime.

It is a super-2 number, since 2×11000200109² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11000200093 and 11000200102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000200139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500100054 + 5500100055.

It is an arithmetic number, because the mean of its divisors is an integer number (5500100055).

Almost surely, 2^11000200109 is an apocalyptic number.

It is an amenable number.

11000200109 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000200109 is an equidigital number, since it uses as much as digits as its factorization.

11000200109 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 14.

The spelling of 11000200109 in words is "eleven billion, two hundred thousand, one hundred nine".