Base | Representation |
---|---|
bin | 1010000000010010111100… |
… | …0101011011000011111101 |
3 | 1102221121102221020111000201 |
4 | 2200010233011123003331 |
5 | 2420211403001231043 |
6 | 35221231143523501 |
7 | 2213511145261036 |
oct | 240045705330375 |
9 | 42847387214021 |
10 | 11000201195773 |
11 | 3561182889309 |
12 | 1297ab5159591 |
13 | 61a4120096ca |
14 | 2a05ac189a8d |
15 | 14121919cc4d |
hex | a012f15b0fd |
11000201195773 has 2 divisors, whose sum is σ = 11000201195774. Its totient is φ = 11000201195772.
The previous prime is 11000201195677. The next prime is 11000201195779. The reversal of 11000201195773 is 37759110200011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5594752894329 + 5405448301444 = 2365323^2 + 2324962^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11000201195773 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000201195779) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500100597886 + 5500100597887.
It is an arithmetic number, because the mean of its divisors is an integer number (5500100597887).
Almost surely, 211000201195773 is an apocalyptic number.
It is an amenable number.
11000201195773 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000201195773 is an equidigital number, since it uses as much as digits as its factorization.
11000201195773 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13230, while the sum is 37.
Adding to 11000201195773 its reverse (37759110200011), we get a palindrome (48759311395784).
The spelling of 11000201195773 in words is "eleven trillion, two hundred one million, one hundred ninety-five thousand, seven hundred seventy-three".
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