Base | Representation |
---|---|
bin | 1010000000010010111100… |
… | …0101011111000100100111 |
3 | 1102221121102221021022120002 |
4 | 2200010233011133010213 |
5 | 2420211403002242244 |
6 | 35221231144131515 |
7 | 2213511145356653 |
oct | 240045705370447 |
9 | 42847387238502 |
10 | 11000201212199 |
11 | 356118289a691 |
12 | 1297ab5166b9b |
13 | 61a412014024 |
14 | 2a05ac191a63 |
15 | 1412191a2a4e |
hex | a012f15f127 |
11000201212199 has 2 divisors, whose sum is σ = 11000201212200. Its totient is φ = 11000201212198.
The previous prime is 11000201212157. The next prime is 11000201212213. The reversal of 11000201212199 is 99121210200011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11000201212199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000201212499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500100606099 + 5500100606100.
It is an arithmetic number, because the mean of its divisors is an integer number (5500100606100).
Almost surely, 211000201212199 is an apocalyptic number.
11000201212199 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000201212199 is an equidigital number, since it uses as much as digits as its factorization.
11000201212199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 29.
The spelling of 11000201212199 in words is "eleven trillion, two hundred one million, two hundred twelve thousand, one hundred ninety-nine".
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