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11000201221957 is a prime number
BaseRepresentation
bin1010000000010010111100…
…0101100001011101000101
31102221121102221021210221111
42200010233011201131011
52420211403003100312
635221231144245021
72213511145430263
oct240045705413505
942847387253844
1011000201221957
1135611828a6a52
121297ab5170771
1361a4120185bc
142a05ac195433
151412191a58a7
hexa012f161745

11000201221957 has 2 divisors, whose sum is σ = 11000201221958. Its totient is φ = 11000201221956.

The previous prime is 11000201221949. The next prime is 11000201222039. The reversal of 11000201221957 is 75912210200011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7419909050401 + 3580292171556 = 2723951^2 + 1892166^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000201221957 - 23 = 11000201221949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000201221907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500100610978 + 5500100610979.

It is an arithmetic number, because the mean of its divisors is an integer number (5500100610979).

Almost surely, 211000201221957 is an apocalyptic number.

It is an amenable number.

11000201221957 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000201221957 is an equidigital number, since it uses as much as digits as its factorization.

11000201221957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2520, while the sum is 31.

Adding to 11000201221957 its reverse (75912210200011), we get a palindrome (86912411421968).

The spelling of 11000201221957 in words is "eleven trillion, two hundred one million, two hundred twenty-one thousand, nine hundred fifty-seven".