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11000208136717 is a prime number
BaseRepresentation
bin1010000000010010111101…
…1111111001101000001101
31102221121110102022010012201
42200010233133321220031
52420211411240333332
635221231552401501
72213511261260032
oct240045737715015
942847412263181
1011000208136717
11356118679a128
121297ab7546291
1361a413599a87
142a05ad075389
15141219abe5e7
hexa012f7f9a0d

11000208136717 has 2 divisors, whose sum is σ = 11000208136718. Its totient is φ = 11000208136716.

The previous prime is 11000208136691. The next prime is 11000208136727. The reversal of 11000208136717 is 71763180200011.

11000208136717 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9887037541956 + 1113170594761 = 3144366^2 + 1055069^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000208136717 - 239 = 10450452322829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000208136727) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500104068358 + 5500104068359.

It is an arithmetic number, because the mean of its divisors is an integer number (5500104068359).

Almost surely, 211000208136717 is an apocalyptic number.

It is an amenable number.

11000208136717 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000208136717 is an equidigital number, since it uses as much as digits as its factorization.

11000208136717 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14112, while the sum is 37.

Adding to 11000208136717 its reverse (71763180200011), we get a palindrome (82763388336728).

The spelling of 11000208136717 in words is "eleven trillion, two hundred eight million, one hundred thirty-six thousand, seven hundred seventeen".