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110002100143 = 1329310993851
BaseRepresentation
bin110011001110010100…
…0101101011110101111
3101111221020100200020011
41212130220231132233
53300241014201033
6122311222434051
710642645265215
oct1463450553657
9344836320204
10110002100143
1142719354a71
121939b592927
13a4b0a83ab0
1454775accb5
152cdc3aeccd
hex199ca2d7af

110002100143 has 16 divisors (see below), whose sum is σ = 122589482400. Its totient is φ = 98006428800.

The previous prime is 110002100077. The next prime is 110002100147. The reversal of 110002100143 is 341001200011.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110002100143 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (13).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110002100147) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1125168 + ... + 1219018.

It is an arithmetic number, because the mean of its divisors is an integer number (7661842650).

Almost surely, 2110002100143 is an apocalyptic number.

110002100143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

110002100143 is a deficient number, since it is larger than the sum of its proper divisors (12587382257).

110002100143 is a wasteful number, since it uses less digits than its factorization.

110002100143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97002.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 110002100143 its reverse (341001200011), we get a palindrome (451003300154).

The spelling of 110002100143 in words is "one hundred ten billion, two million, one hundred thousand, one hundred forty-three".

Divisors: 1 13 29 377 3109 40417 90161 93851 1172093 1220063 2721679 35381827 291782759 3793175867 8461700011 110002100143