Base | Representation |
---|---|
bin | 11001000000101111011100… |
… | …010010101110000000010111 |
3 | 112102111002122201022010022121 |
4 | 121000233130102232000113 |
5 | 103404233301421444112 |
6 | 1025542134005040411 |
7 | 32112250444420645 |
oct | 3100573422560027 |
9 | 472432581263277 |
10 | 110002103312407 |
11 | 320606a2630a09 |
12 | 104071899b6107 |
13 | 494c1ccc7bc07 |
14 | 1d241b7410195 |
15 | cab6191d1407 |
hex | 640bdc4ae017 |
110002103312407 has 2 divisors, whose sum is σ = 110002103312408. Its totient is φ = 110002103312406.
The previous prime is 110002103312279. The next prime is 110002103312443. The reversal of 110002103312407 is 704213301200011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110002103312407 - 27 = 110002103312279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110002103315407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001051656203 + 55001051656204.
It is an arithmetic number, because the mean of its divisors is an integer number (55001051656204).
Almost surely, 2110002103312407 is an apocalyptic number.
110002103312407 is a deficient number, since it is larger than the sum of its proper divisors (1).
110002103312407 is an equidigital number, since it uses as much as digits as its factorization.
110002103312407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 110002103312407 its reverse (704213301200011), we get a palindrome (814215404512418).
The spelling of 110002103312407 in words is "one hundred ten trillion, two billion, one hundred three million, three hundred twelve thousand, four hundred seven".
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