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11000211222193 is a prime number
BaseRepresentation
bin1010000000010010111110…
…1011101010111010110001
31102221121110122002212200121
42200010233223222322301
52420211413033102233
635221232142450241
72213511326430424
oct240045753527261
942847418085617
1011000211222193
113561188507306
121297ab8593981
1361a41410a2bb
142a05ad6399bb
15141219ecd92d
hexa012faeaeb1

11000211222193 has 2 divisors, whose sum is σ = 11000211222194. Its totient is φ = 11000211222192.

The previous prime is 11000211222191. The next prime is 11000211222251. The reversal of 11000211222193 is 39122211200011.

11000211222193 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10650484466064 + 349726756129 = 3263508^2 + 591377^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000211222193 - 21 = 11000211222191 is a prime.

Together with 11000211222191, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11000211222191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500105611096 + 5500105611097.

It is an arithmetic number, because the mean of its divisors is an integer number (5500105611097).

Almost surely, 211000211222193 is an apocalyptic number.

It is an amenable number.

11000211222193 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000211222193 is an equidigital number, since it uses as much as digits as its factorization.

11000211222193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 25.

The spelling of 11000211222193 in words is "eleven trillion, two hundred eleven million, two hundred twenty-two thousand, one hundred ninety-three".