11000211713 has 2 divisors, whose sum is σ = 11000211714. Its totient is φ = 11000211712.

The previous prime is 11000211701. The next prime is 11000211721. The reversal of 11000211713 is 31711200011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9926535424 + 1073676289 = 99632^2 + 32767^2 .

It is an emirp because it is prime and its reverse (31711200011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000211713 - 2¹⁴ = 11000195329 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11000211691 and 11000211700.

It is not a weakly prime, because it can be changed into another prime (11000271713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500105856 + 5500105857.

It is an arithmetic number, because the mean of its divisors is an integer number (5500105857).

Almost surely, 2^11000211713 is an apocalyptic number.

It is an amenable number.

11000211713 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000211713 is an equidigital number, since it uses as much as digits as its factorization.

11000211713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 42, while the sum is 17.

Adding to 11000211713 its reverse (31711200011), we get a palindrome (42711411724).

The spelling of 11000211713 in words is "eleven billion, two hundred eleven thousand, seven hundred thirteen".