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110002122119971 is a prime number
BaseRepresentation
bin11001000000101111011101…
…011010011101101100100011
3112102111002201000200122110001
4121000233131122131230203
5103404233321230314341
61025542135520120431
732112251063322334
oct3100573532355443
9472432630618401
10110002122119971
1132060702207354
1210407194166117
13494c203b35653
141d241b9b0828b
15cab61ab98d31
hex640bdd69db23

110002122119971 has 2 divisors, whose sum is σ = 110002122119972. Its totient is φ = 110002122119970.

The previous prime is 110002122119921. The next prime is 110002122120031. The reversal of 110002122119971 is 179911221200011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 110002122119971 - 213 = 110002122111779 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 110002122119971.

It is not a weakly prime, because it can be changed into another prime (110002122119921) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001061059985 + 55001061059986.

It is an arithmetic number, because the mean of its divisors is an integer number (55001061059986).

Almost surely, 2110002122119971 is an apocalyptic number.

110002122119971 is a deficient number, since it is larger than the sum of its proper divisors (1).

110002122119971 is an equidigital number, since it uses as much as digits as its factorization.

110002122119971 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4536, while the sum is 37.

Adding to 110002122119971 its reverse (179911221200011), we get a palindrome (289913343319982).

The spelling of 110002122119971 in words is "one hundred ten trillion, two billion, one hundred twenty-two million, one hundred nineteen thousand, nine hundred seventy-one".