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110002122120031 is a prime number
BaseRepresentation
bin11001000000101111011101…
…011010011101101101011111
3112102111002201000200122112021
4121000233131122131231133
5103404233321230320111
61025542135520121011
732112251063322451
oct3100573532355537
9472432630618467
10110002122120031
11320607022073a9
1210407194166167
13494c203b3569b
141d241b9b082d1
15cab61ab98d71
hex640bdd69db5f

110002122120031 has 2 divisors, whose sum is σ = 110002122120032. Its totient is φ = 110002122120030.

The previous prime is 110002122119971. The next prime is 110002122120131. The reversal of 110002122120031 is 130021221200011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 110002122120031 - 229 = 110001585249119 is a prime.

It is a super-2 number, since 2×1100021221200312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110002122119987 and 110002122120014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110002122120131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001061060015 + 55001061060016.

It is an arithmetic number, because the mean of its divisors is an integer number (55001061060016).

Almost surely, 2110002122120031 is an apocalyptic number.

110002122120031 is a deficient number, since it is larger than the sum of its proper divisors (1).

110002122120031 is an equidigital number, since it uses as much as digits as its factorization.

110002122120031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 110002122120031 its reverse (130021221200011), we get a palindrome (240023343320042).

The spelling of 110002122120031 in words is "one hundred ten trillion, two billion, one hundred twenty-two million, one hundred twenty thousand, thirty-one".