Base | Representation |
---|---|
bin | 1010000000010010111110… |
… | …1111011111000100000011 |
3 | 1102221121110200222200110022 |
4 | 2200010233233133010003 |
5 | 2420211413312102321 |
6 | 35221232220124055 |
7 | 2213511341064062 |
oct | 240045757370403 |
9 | 42847420880408 |
10 | 11000212222211 |
11 | 356118902a673 |
12 | 1297ab899662b |
13 | 61a41439a524 |
14 | 2a05ad81a1d9 |
15 | 14121a129dab |
hex | a012fbdf103 |
11000212222211 has 2 divisors, whose sum is σ = 11000212222212. Its totient is φ = 11000212222210.
The previous prime is 11000212222189. The next prime is 11000212222243. The reversal of 11000212222211 is 11222221200011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11000212222211 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11000212222211.
It is not a weakly prime, because it can be changed into another prime (11000212222261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500106111105 + 5500106111106.
It is an arithmetic number, because the mean of its divisors is an integer number (5500106111106).
Almost surely, 211000212222211 is an apocalyptic number.
11000212222211 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000212222211 is an equidigital number, since it uses as much as digits as its factorization.
11000212222211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 11000212222211 its reverse (11222221200011), we get a palindrome (22222433422222).
The spelling of 11000212222211 in words is "eleven trillion, two hundred twelve million, two hundred twenty-two thousand, two hundred eleven".
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