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110002131400417 is a prime number
BaseRepresentation
bin11001000000101111011101…
…111101110111011011100001
3112102111002201200011010211021
4121000233131331313123201
5103404233331114303132
61025542140451045441
732112251235234124
oct3100573575673341
9472432650133737
10110002131400417
1132060707475943
12104071972a0881
13494c205a34839
141d241bb0423bb
15cab61b8cd997
hex640bddf776e1

110002131400417 has 2 divisors, whose sum is σ = 110002131400418. Its totient is φ = 110002131400416.

The previous prime is 110002131400361. The next prime is 110002131400433. The reversal of 110002131400417 is 714004131200011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106639514342881 + 3362617057536 = 10326641^2 + 1833744^2 .

It is a cyclic number.

It is not a de Polignac number, because 110002131400417 - 219 = 110002130876129 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110002131400391 and 110002131400400.

It is not a weakly prime, because it can be changed into another prime (110002131200417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001065700208 + 55001065700209.

It is an arithmetic number, because the mean of its divisors is an integer number (55001065700209).

Almost surely, 2110002131400417 is an apocalyptic number.

It is an amenable number.

110002131400417 is a deficient number, since it is larger than the sum of its proper divisors (1).

110002131400417 is an equidigital number, since it uses as much as digits as its factorization.

110002131400417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 672, while the sum is 25.

Adding to 110002131400417 its reverse (714004131200011), we get a palindrome (824006262600428).

The spelling of 110002131400417 in words is "one hundred ten trillion, two billion, one hundred thirty-one million, four hundred thousand, four hundred seventeen".